If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2+11=38
We move all terms to the left:
x2+11-(38)=0
We add all the numbers together, and all the variables
x^2-27=0
a = 1; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·1·(-27)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*1}=\frac{0-6\sqrt{3}}{2} =-\frac{6\sqrt{3}}{2} =-3\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*1}=\frac{0+6\sqrt{3}}{2} =\frac{6\sqrt{3}}{2} =3\sqrt{3} $
| 6x^2+36= | | 5^x-2=29 | | 30=13/10b | | 1x=9x-10 | | 5(2y-3)=7(2y+3) | | y−7=21 | | 7x+1+2x+11=90 | | x/x+2+7/x-5=14/x^2-3x-10 | | 3(2a-5)+4(3a+2)=11 | | 8m=416,m= | | 5(2y-3)=7(2y=3) | | 2x÷5-3÷5=11÷5 | | 20=-4v | | 4(7^x)=16 | | 30=6(5+4y) | | 273=87-v | | 3*(x-4)=7x+8 | | 7^2-4x+√9=15x2-2x | | 5x+2x=x | | 2.8-2x=-6.2 | | 291=5x+1 | | 3u-15=42 | | x/x-3-7/x+5=24/x^2+2x-15 | | Y=5x-¹ | | 4x-2-2x=xx-6 | | (10x)(4x^-7)=40x^-8 | | 4x-9=-3x+40 | | 3/4{x+1}=12 | | 12=5x+1 | | 1/4(x-1)+3x=2 | | 285=5x+1 | | 4x+12=-12-5x |