x2+10x-32=3(x-8)

Solution for x2+10x-32=3(x-8) equation:

x2+10x-32=3(x-8)

We move all terms to the left:

x2+10x-32-(3(x-8))=0

We add all the numbers together, and all the variables

x^2+10x-(3(x-8))-32=0


We calculate terms in parentheses: -(3(x-8)), so:

3(x-8)

We multiply parentheses

3x-24

Back to the equation:

-(3x-24)


We get rid of parentheses

x^2+10x-3x+24-32=0

We add all the numbers together, and all the variables

x^2+7x-8=0

a = 1; b = 7; c = -8;
Δ = b2-4ac
Δ = 72-4·1·(-8)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*1}=\frac{2}{2}
=1
$