x2+10x+4.75=0

Solution for x2+10x+4.75=0 equation:

x2+10x+4.75=0

We add all the numbers together, and all the variables

x^2+10x+4.75=0

a = 1; b = 10; c = +4.75;
Δ = b2-4ac
Δ = 102-4·1·4.75
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-9}{2*1}=\frac{-19}{2}
=-9+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+9}{2*1}=\frac{-1}{2}
=-1/2
$