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x2+10x+(-108/3.14)=0
We add all the numbers together, and all the variables
x^2+10x+(-108/3.14)=0
We get rid of parentheses
x^2+10x-108/3.14=0
We multiply all the terms by the denominator
x^2*3.14+10x*3.14-108=0
Wy multiply elements
3.14x^2+31.4x-108=0
a = 3.14; b = 31.4; c = -108;
Δ = b2-4ac
Δ = 31.42-4·3.14·(-108)
Δ = 2342.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31.4)-\sqrt{2342.44}}{2*3.14}=\frac{-31.4-\sqrt{2342.44}}{6.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31.4)+\sqrt{2342.44}}{2*3.14}=\frac{-31.4+\sqrt{2342.44}}{6.28} $
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