x2+10+3x+16=180

Solution for x2+10+3x+16=180 equation:

x2+10+3x+16=180

We move all terms to the left:

x2+10+3x+16-(180)=0

We add all the numbers together, and all the variables

x^2+3x-154=0

a = 1; b = 3; c = -154;
Δ = b2-4ac
Δ = 32-4·1·(-154)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-25}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+25}{2*1}=\frac{22}{2}
=11
$