x2+1.632x-1=0

Solution for x2+1.632x-1=0 equation:

x2+1.632x-1=0

We add all the numbers together, and all the variables

x^2+1.632x-1=0

a = 1; b = 1.632; c = -1;
Δ = b2-4ac
Δ = 1.6322-4·1·(-1)
Δ = 6.663424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.632)-\sqrt{6.663424}}{2*1}=\frac{-1.632-\sqrt{6.663424}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.632)+\sqrt{6.663424}}{2*1}=\frac{-1.632+\sqrt{6.663424}}{2}
$