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x/8x+6+3x-2=37
We move all terms to the left:
x/8x+6+3x-2-(37)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
3x+x/8x-33=0
We multiply all the terms by the denominator
3x*8x+x-33*8x=0
We add all the numbers together, and all the variables
x+3x*8x-33*8x=0
Wy multiply elements
24x^2+x-264x=0
We add all the numbers together, and all the variables
24x^2-263x=0
a = 24; b = -263; c = 0;
Δ = b2-4ac
Δ = -2632-4·24·0
Δ = 69169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{69169}=263$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-263)-263}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-263)+263}{2*24}=\frac{526}{48} =10+23/24 $
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