x/8+2/x=x/4

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Solution for x/8+2/x=x/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/8+2/x = x/4 // - x/4

x/8-(x/4)+2/x = 0

2*x^-1-1/8*x^1 = 0

(2*x^0-1/8*x^2)/(x^1) = 0 // * x^2

x^1*(2*x^0-1/8*x^2) = 0

x^1

(-1/8)*x^2+2 = 0

(-1/8)*x^2+2 = 0

DELTA = 0^2-(2*4*(-1/8))

DELTA = 1

DELTA > 0

x = (1^(1/2)+0)/(2*(-1/8)) or x = (0-1^(1/2))/(2*(-1/8))

x = -4 or x = 4

x in { -4, 4} 

x in { -4, 4 }

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