x/7(2+x)=35

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Solution for x/7(2+x)=35 equation: 



x/7(2+x)=35

We move all terms to the left:

x/7(2+x)-(35)=0



Domain of the equation: 7(2+x)!=0

x∈R



We add all the numbers together, and all the variables

x/7(x+2)-35=0

We multiply all the terms by the denominator


x-35*7(x+2)=0

Wy multiply elements

x-245x(x=0

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