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x/5x-12=2x+6
We move all terms to the left:
x/5x-12-(2x+6)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
x/5x-2x-6-12=0
We multiply all the terms by the denominator
x-2x*5x-6*5x-12*5x=0
Wy multiply elements
-10x^2+x-30x-60x=0
We add all the numbers together, and all the variables
-10x^2-89x=0
a = -10; b = -89; c = 0;
Δ = b2-4ac
Δ = -892-4·(-10)·0
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7921}=89$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-89)-89}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-89)+89}{2*-10}=\frac{178}{-20} =-8+9/10 $
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