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x/5x+3(x+14)=202
We move all terms to the left:
x/5x+3(x+14)-(202)=0
Domain of the equation: 5x!=0We multiply parentheses
x!=0/5
x!=0
x∈R
x/5x+3x+42-202=0
We multiply all the terms by the denominator
x+3x*5x+42*5x-202*5x=0
Wy multiply elements
15x^2+x+210x-1010x=0
We add all the numbers together, and all the variables
15x^2-799x=0
a = 15; b = -799; c = 0;
Δ = b2-4ac
Δ = -7992-4·15·0
Δ = 638401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{638401}=799$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-799)-799}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-799)+799}{2*15}=\frac{1598}{30} =53+4/15 $
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