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x/4x+3(x-2)=22*
We move all terms to the left:
x/4x+3(x-2)-(22*)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
x/4x+3(x-2)-0=0
We add all the numbers together, and all the variables
x/4x+3(x-2)=0
We multiply parentheses
x/4x+3x-6=0
We multiply all the terms by the denominator
x+3x*4x-6*4x=0
Wy multiply elements
12x^2+x-24x=0
We add all the numbers together, and all the variables
12x^2-23x=0
a = 12; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·12·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*12}=\frac{46}{24} =1+11/12 $
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