x/4-12(6-x)=7x+3(6-2x)-1

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Solution for x/4-12(6-x)=7x+3(6-2x)-1 equation: 



x/4-12(6-x)=7x+3(6-2x)-1

We move all terms to the left:

x/4-12(6-x)-(7x+3(6-2x)-1)=0

We add all the numbers together, and all the variables

x/4-12(-1x+6)-(7x+3(-2x+6)-1)=0

We multiply parentheses

x/4+12x-(7x+3(-2x+6)-1)-72=0

We multiply all the terms by the denominator


x+12x*4-((7x+3(-2x+6)-1))*4-72*4=0

We add all the numbers together, and all the variables

x+12x*4-((7x+3(-2x+6)-1))*4-288=0

Wy multiply elements

x+48x-((7x+3(-2x+6)-1))*4-288=0

We add all the numbers together, and all the variables

49x-((7x+3(-2x+6)-1))*4-288=0

We move all terms containing x to the left, all other terms to the right

49x-((7x+3(-2x+6)-1))*4=288

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