x/4(x-1)=2(x+1)

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Solution for x/4(x-1)=2(x+1) equation: 



x/4(x-1)=2(x+1)

We move all terms to the left:

x/4(x-1)-(2(x+1))=0



Domain of the equation: 4(x-1)!=0

x∈R



We multiply all the terms by the denominator


x-((2(x+1)))*4(x-1)=0



We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





We calculate terms in parentheses: -((2(x+1)))*4(x-1), so:

(2(x+1)))*4(x-1





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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