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x/4(1-x)+3x=-2x-2
We move all terms to the left:
x/4(1-x)+3x-(-2x-2)=0
Domain of the equation: 4(1-x)!=0We add all the numbers together, and all the variables
x∈R
x/4(-1x+1)+3x-(-2x-2)=0
We add all the numbers together, and all the variables
3x+x/4(-1x+1)-(-2x-2)=0
We get rid of parentheses
3x+x/4(-1x+1)+2x+2=0
We multiply all the terms by the denominator
3x*4(-1x+1)+x+2x*4(-1x+1)+2*4(-1x+1)=0
We add all the numbers together, and all the variables
x+3x*4(-1x+1)+2x*4(-1x+1)+2*4(-1x+1)=0
Wy multiply elements
12x^2(-+8x^2(-+8x(-+x=0
We use the square of the difference formula
12x^2(-8x^2(-8x(-x=0
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