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x/3x-5=2x+6
We move all terms to the left:
x/3x-5-(2x+6)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
x/3x-2x-6-5=0
We multiply all the terms by the denominator
x-2x*3x-6*3x-5*3x=0
Wy multiply elements
-6x^2+x-18x-15x=0
We add all the numbers together, and all the variables
-6x^2-32x=0
a = -6; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·(-6)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*-6}=\frac{64}{-12} =-5+1/3 $
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