x/3=2+(x-20)/5

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Solution for x/3=2+(x-20)/5 equation: 



x/3=2+(x-20)/5

We move all terms to the left:

x/3-(2+(x-20)/5)=0

We calculate fractions


5x^2/()+(-(2+(x-20)*3)/()=0



We calculate terms in parentheses: +(-(2+(x-20)*3)/(), so:

-(2+(x-20)*3)/(

We multiply all the terms by the denominator


-(2+(x-20)*3)



We calculate terms in parentheses: -(2+(x-20)*3), so:

2+(x-20)*3

determiningTheFunctionDomain
(x-20)*3+2

We multiply parentheses

3x-60+2

We add all the numbers together, and all the variables

3x-58

Back to the equation:

-(3x-58)



We get rid of parentheses

-3x+58

Back to the equation:

+(-3x+58)



We get rid of parentheses

5x^2/()-3x+58=0

We multiply all the terms by the denominator


5x^2-3x*()+58*()=0

We add all the numbers together, and all the variables

5x^2-3x*()=0

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