x/3-(2x+1)/2=x/6-x

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Solution for x/3-(2x+1)/2=x/6-x equation: 



x/3-(2x+1)/2=x/6-x

We move all terms to the left:

x/3-(2x+1)/2-(x/6-x)=0



Domain of the equation: 6-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-6

x!=-6/1

x!=-6

x∈R



We add all the numbers together, and all the variables

x/3-(2x+1)/2-(-1x+x/6)=0

We get rid of parentheses

x/3-(2x+1)/2+1x-x/6=0

We calculate fractions

There is no solution for this equation

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