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x/2-7=1/3(5x-42)
We move all terms to the left:
x/2-7-(1/3(5x-42))=0
Domain of the equation: 3(5x-42))!=0We calculate fractions
x∈R
(3x^25/(6x5+()/(6x5-7=0
We do not support expression: x^25
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