x/2+y/3=-4/3;x/2+2y=-3

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for example:
2x+y=8
x+3y=14

Solution for x/2+y/3=-4/3;x/2+2y=-3 system of equations: 


  • /| x/2+y/3-(-4/3) = 0| x/2+2*y+3 = 0
  • We try to solve the equation: x/2+y/3-(-4/3) = 0
  • 1/2*x+1/3*y+4/3 = 0 // - 1/2*x+4/3
  • 1/3*y = -(1/2*x+4/3) // : 1/3
  • y = (-(1/2*x+4/3))/1/3
  • y = -3*(1/2*x+4/3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| x/2-3*2*(1/2*x+4/3)+3 = 0| y = -3*(1/2*x+4/3)
  • x/2-6*(1/2*x+4/3)+3 = 0
  • 3-5/2*x-8 = 0
  • -5/2*x-5 = 0
  • -5/2*x-5 = 0 // + 5
  • -5/2*x = 5 // : -5/2
  • x = 5/(-5/2)
  • x = -2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -3*(1/2*x+4/3): 
  • y = -3*(4/3-2*1/2)
  • y = -3*(4/3-1)
  • y = -3*1/3
  • y = -1
  • We get a system of equations:
  • /| y = -1| x = -2

 

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