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x/2(x-5)=5x+23
We move all terms to the left:
x/2(x-5)-(5x+23)=0
Domain of the equation: 2(x-5)!=0We get rid of parentheses
x∈R
x/2(x-5)-5x-23=0
We multiply all the terms by the denominator
x-5x*2(x-5)-23*2(x-5)=0
Wy multiply elements
-10x^2(x-46x(x+x=0
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