x/12-12/x=0

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Solution for x/12-12/x=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/12-(12/x) = 0

x/12-12*x^-1 = 0

1/12*x^1-12*x^-1 = 0

(1/12*x^2-12*x^0)/(x^1) = 0 // * x^2

x^1*(1/12*x^2-12*x^0) = 0

x^1

(1/12)*x^2-12 = 0

(1/12)*x^2-12 = 0

DELTA = 0^2-(-12*4*(1/12))

DELTA = 4

DELTA > 0

x = (4^(1/2)+0)/(2*(1/12)) or x = (0-4^(1/2))/(2*(1/12))

x = 12 or x = -12

x in { -12, 12} 

x in { -12, 12 }

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