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x/(x-5)=x/(x-4)
We move all terms to the left:
x/(x-5)-(x/(x-4))=0
Domain of the equation: (x-5)!=0
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
Domain of the equation: (x-4))!=0We calculate fractions
x∈R
(-3x^2)/((x-5)*(x-4)))+(-(x*(x-5))/((x-5)*(x-4)))=0
We calculate terms in parentheses: -(x*(x-5))/((x-5)*(x-4))), so:We get rid of parentheses
x*(x-5))/((x-5)*(x-4))
We multiply all the terms by the denominator
x*(x-5))
We multiply parentheses
x^2-5x^2
We add all the numbers together, and all the variables
-4x^2
Back to the equation:
-(-4x^2)
(-3x^2)/((x-5)*(x-4)))+(+4x^2=0
We multiply all the terms by the denominator
(-3x^2)+4x^2*((x-5)*(x-4)))+(=0
We get rid of parentheses
-3x^2+4x^2*((x-5)*(x-4)))+(=0
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