x/(x-2)-5=2/(x-2)

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Solution for x/(x-2)-5=2/(x-2) equation:


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

x/(x-2)-5 = 2/(x-2) // - 2/(x-2)

x/(x-2)-(2/(x-2))-5 = 0

x/(x-2)-2*(x-2)^-1-5 = 0

x/(x-2)-2/(x-2)-5 = 0

x/(x-2)-2/(x-2)+(-5*(x-2))/(x-2) = 0

x-5*(x-2)-2 = 0

x-5*x-2+10 = 0

8-4*x = 0

(8-4*x)/(x-2) = 0

(8-4*x)/(x-2) = 0 // * x-2

8-4*x = 0

8-4*x = 0 // - 8

-4*x = -8 // : -4

x = -8/(-4)

x = 2

x in { 2}

x belongs to the empty set

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