x/(x+1)-3/(x+2)=1

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Solution for x/(x+1)-3/(x+2)=1 equation:


D( x )

x+2 = 0

x+1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-2) U (-2:-1) U (-1:+oo)

x/(x+1)-(3/(x+2)) = 1 // - 1

x/(x+1)-(3/(x+2))-1 = 0

x/(x+1)-3*(x+2)^-1-1 = 0

x/(x+1)-3/(x+2)-1 = 0

(x*(x+2))/((x+1)*(x+2))+(-3*(x+1))/((x+1)*(x+2))+(-1*(x+1)*(x+2))/((x+1)*(x+2)) = 0

x*(x+2)-3*(x+1)-1*(x+1)*(x+2) = 0

x^2-x^2-x-3*x-3-2 = 0

-4*x-5 = 0

(-4*x-5)/((x+1)*(x+2)) = 0

(-4*x-5)/((x+1)*(x+2)) = 0 // * (x+1)*(x+2)

-4*x-5 = 0

-4*x-5 = 0 // + 5

-4*x = 5 // : -4

x = 5/(-4)

x = -5/4

x = -5/4

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