x.x2+4x+6=x2-2x+18

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Solution for x.x2+4x+6=x2-2x+18 equation: 



x.x^2+4x+6=x2-2x+18

We move all terms to the left:

x.x^2+4x+6-(x2-2x+18)=0

We add all the numbers together, and all the variables

-(+x^2-2x+18)+x.x^2+4x+6=0

We add all the numbers together, and all the variables

-(+x^2-2x+18)+4x+x.x^2+6=0

We get rid of parentheses

-x^2+2x+4x+x.x^2-18+6=0

We add all the numbers together, and all the variables

-1x^2+6x+x.x^2-12=0

We move all terms containing x to the left, all other terms to the right

-1x^2+6x+x.x^2=12

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