x.2x-2=3(x-1)-5(6-2x)

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Solution for x.2x-2=3(x-1)-5(6-2x) equation: 



x.2x-2=3(x-1)-5(6-2x)

We move all terms to the left:

x.2x-2-(3(x-1)-5(6-2x))=0

We add all the numbers together, and all the variables

x.2x-(3(x-1)-5(-2x+6))-2=0



We calculate terms in parentheses: -(3(x-1)-5(-2x+6)), so:

3(x-1)-5(-2x+6)

We multiply parentheses

3x+10x-3-30

We add all the numbers together, and all the variables

13x-33

Back to the equation:

-(13x-33)



We get rid of parentheses

x.2x-13x+33-2=0

We add all the numbers together, and all the variables

-13x+x.2x+31=0

We move all terms containing x to the left, all other terms to the right

-13x+x.2x=-31

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