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x-9/2x+6=x+5/x
We move all terms to the left:
x-9/2x+6-(x+5/x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-9/2x-(+x+5/x)+6=0
We get rid of parentheses
x-9/2x-x-5/x+6=0
We calculate fractions
x-x+(-9x)/2x^2+(-10x)/2x^2+6=0
We add all the numbers together, and all the variables
(-9x)/2x^2+(-10x)/2x^2+6=0
We multiply all the terms by the denominator
(-9x)+(-10x)+6*2x^2=0
Wy multiply elements
12x^2+(-9x)+(-10x)=0
We get rid of parentheses
12x^2-9x-10x=0
We add all the numbers together, and all the variables
12x^2-19x=0
a = 12; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·12·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*12}=\frac{38}{24} =1+7/12 $
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