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x-8=480/2x
We move all terms to the left:
x-8-(480/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+480/2x)-8=0
We get rid of parentheses
x-480/2x-8=0
We multiply all the terms by the denominator
x*2x-8*2x-480=0
Wy multiply elements
2x^2-16x-480=0
a = 2; b = -16; c = -480;
Δ = b2-4ac
Δ = -162-4·2·(-480)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-64}{2*2}=\frac{-48}{4} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+64}{2*2}=\frac{80}{4} =20 $
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