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x-8/3x=-10
We move all terms to the left:
x-8/3x-(-10)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x-8/3x+10=0
We multiply all the terms by the denominator
x*3x+10*3x-8=0
Wy multiply elements
3x^2+30x-8=0
a = 3; b = 30; c = -8;
Δ = b2-4ac
Δ = 302-4·3·(-8)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{249}}{2*3}=\frac{-30-2\sqrt{249}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{249}}{2*3}=\frac{-30+2\sqrt{249}}{6} $
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