x-7/2x+1=x-4/x

Solution for x-7/2x+1=x-4/x equation:

x-7/2x+1=x-4/x

We move all terms to the left:

x-7/2x+1-(x-4/x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-7/2x-(+x-4/x)+1=0

We get rid of parentheses

x-7/2x-x+4/x+1=0

We calculate fractions


x-x+(-7x)/2x^2+8x/2x^2+1=0

We add all the numbers together, and all the variables

(-7x)/2x^2+8x/2x^2+1=0

We multiply all the terms by the denominator


(-7x)+8x+1*2x^2=0

We add all the numbers together, and all the variables

8x+(-7x)+1*2x^2=0

Wy multiply elements

2x^2+8x+(-7x)=0

We get rid of parentheses

2x^2+8x-7x=0

We add all the numbers together, and all the variables

2x^2+x=0

a = 2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*2}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*2}=\frac{0}{4}
=0
$