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x-6=3/2x
We move all terms to the left:
x-6-(3/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+3/2x)-6=0
We get rid of parentheses
x-3/2x-6=0
We multiply all the terms by the denominator
x*2x-6*2x-3=0
Wy multiply elements
2x^2-12x-3=0
a = 2; b = -12; c = -3;
Δ = b2-4ac
Δ = -122-4·2·(-3)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{42}}{2*2}=\frac{12-2\sqrt{42}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{42}}{2*2}=\frac{12+2\sqrt{42}}{4} $
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