x-6=(x-2)(x+3)

Solution for x-6=(x-2)(x+3) equation:

x-6=(x-2)(x+3)

We move all terms to the left:

x-6-((x-2)(x+3))=0

We multiply parentheses ..

-((+x^2+3x-2x-6))+x-6=0


We calculate terms in parentheses: -((+x^2+3x-2x-6)), so:

(+x^2+3x-2x-6)

We get rid of parentheses

x^2+3x-2x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)


We add all the numbers together, and all the variables

x-(x^2+x-6)-6=0

We get rid of parentheses

-x^2+x-x+6-6=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$