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x-5=x2+7
We move all terms to the left:
x-5-(x2+7)=0
We add all the numbers together, and all the variables
-(+x^2+7)+x-5=0
We get rid of parentheses
-x^2+x-7-5=0
We add all the numbers together, and all the variables
-1x^2+x-12=0
a = -1; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·(-1)·(-12)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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