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x-5=-5/2x+2
We move all terms to the left:
x-5-(-5/2x+2)=0
Domain of the equation: 2x+2)!=0We get rid of parentheses
x∈R
x+5/2x-2-5=0
We multiply all the terms by the denominator
x*2x-2*2x-5*2x+5=0
Wy multiply elements
2x^2-4x-10x+5=0
We add all the numbers together, and all the variables
2x^2-14x+5=0
a = 2; b = -14; c = +5;
Δ = b2-4ac
Δ = -142-4·2·5
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{39}}{2*2}=\frac{14-2\sqrt{39}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{39}}{2*2}=\frac{14+2\sqrt{39}}{4} $
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