x-58=10(2x+3)-12

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Solution for x-58=10(2x+3)-12 equation: 



x-58=10(2x+3)-12

We move all terms to the left:

x-58-(10(2x+3)-12)=0



We calculate terms in parentheses: -(10(2x+3)-12), so:

10(2x+3)-12

We multiply parentheses

20x+30-12

We add all the numbers together, and all the variables

20x+18

Back to the equation:

-(20x+18)



We get rid of parentheses

x-20x-18-58=0

We add all the numbers together, and all the variables

-19x-76=0

We move all terms containing x to the left, all other terms to the right

-19x=76

x=76/-19

x=-4

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