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x-5/6x=10
We move all terms to the left:
x-5/6x-(10)=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
x*6x-10*6x-5=0
Wy multiply elements
6x^2-60x-5=0
a = 6; b = -60; c = -5;
Δ = b2-4ac
Δ = -602-4·6·(-5)
Δ = 3720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3720}=\sqrt{4*930}=\sqrt{4}*\sqrt{930}=2\sqrt{930}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{930}}{2*6}=\frac{60-2\sqrt{930}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{930}}{2*6}=\frac{60+2\sqrt{930}}{12} $
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