If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-x-(5/2)-(3/5) = 1/2 // - 1/2
x-x-(5/2)-(3/5)-(1/2) = 0
x-x-5/2-3/5-1/2 = 0
-18/5 = 0
x belongs to the empty set
x belongs to the empty set
| 9*x^2+4+19=100 | | 7/9.6 | | (2k+1)x+(k-2)y+3k-1=0 | | 7x-24=2x-9 | | (39)/(3x-12)=(13/3) | | ln((4x-3)^(1/2)) | | 7/9.7/11 | | 20/21 | | 36÷56/7 | | 4.3x=x+53 | | 1.2(2x+9)=6 | | 4-3s=2s+17 | | 2.5x+2.5y=5 | | 0.03-x=0.731x | | 2(x+4)+10=12x-2 | | 5p-18=-6+3p | | 9m-24=-72+m | | 20log(x)=-56 | | 6s-8=19+3s | | 0.03-x=0.713x | | 5m-11=-11+7m | | 27y^3=0 | | 13x+10=36x | | 3cd= | | 10x-4=6x+8x | | y=2xgraph | | 75a-25b=-1250 | | 73a-25b=-1250 | | v^3=-31 | | sov^3=-31 | | solv^3=-31 | | 48x-9/2x^2=0 |