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x-5(2x-3)=3(x-1)+4
We move all terms to the left:
x-5(2x-3)-(3(x-1)+4)=0
We multiply parentheses
x-10x-(3(x-1)+4)+15=0
We calculate terms in parentheses: -(3(x-1)+4), so:We add all the numbers together, and all the variables
3(x-1)+4
We multiply parentheses
3x-3+4
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
-9x-(3x+1)+15=0
We get rid of parentheses
-9x-3x-1+15=0
We add all the numbers together, and all the variables
-12x+14=0
We move all terms containing x to the left, all other terms to the right
-12x=-14
x=-14/-12
x=1+1/6
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