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x-40=1/3x
We move all terms to the left:
x-40-(1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+1/3x)-40=0
We get rid of parentheses
x-1/3x-40=0
We multiply all the terms by the denominator
x*3x-40*3x-1=0
Wy multiply elements
3x^2-120x-1=0
a = 3; b = -120; c = -1;
Δ = b2-4ac
Δ = -1202-4·3·(-1)
Δ = 14412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14412}=\sqrt{4*3603}=\sqrt{4}*\sqrt{3603}=2\sqrt{3603}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-2\sqrt{3603}}{2*3}=\frac{120-2\sqrt{3603}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+2\sqrt{3603}}{2*3}=\frac{120+2\sqrt{3603}}{6} $
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