x-4/3x-4=3

Solution for x-4/3x-4=3 equation:

x-4/3x-4=3

We move all terms to the left:

x-4/3x-4-(3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x-4/3x-7=0

We multiply all the terms by the denominator


x*3x-7*3x-4=0

Wy multiply elements

3x^2-21x-4=0

a = 3; b = -21; c = -4;
Δ = b2-4ac
Δ = -212-4·3·(-4)
Δ = 489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{489}}{2*3}=\frac{21-\sqrt{489}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{489}}{2*3}=\frac{21+\sqrt{489}}{6}
$