x-4+3x=4x(x+1)-2

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Solution for x-4+3x=4x(x+1)-2 equation: 



x-4+3x=4x(x+1)-2

We move all terms to the left:

x-4+3x-(4x(x+1)-2)=0

We add all the numbers together, and all the variables

4x-(4x(x+1)-2)-4=0



We calculate terms in parentheses: -(4x(x+1)-2), so:

4x(x+1)-2

We multiply parentheses

4x^2+4x-2

Back to the equation:

-(4x^2+4x-2)



We get rid of parentheses

-4x^2+4x-4x+2-4=0

We add all the numbers together, and all the variables

-4x^2-2=0

a = -4; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-4)·(-2)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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