x-4(8x-1)=40+5x

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Solution for x-4(8x-1)=40+5x equation: 



x-4(8x-1)=40+5x

We move all terms to the left:

x-4(8x-1)-(40+5x)=0

We add all the numbers together, and all the variables

x-4(8x-1)-(5x+40)=0

We multiply parentheses

x-32x-(5x+40)+4=0

We get rid of parentheses

x-32x-5x-40+4=0

We add all the numbers together, and all the variables

-36x-36=0

We move all terms containing x to the left, all other terms to the right

-36x=36

x=36/-36

x=-1

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