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x-4(2+3x)=2(5x-3)
We move all terms to the left:
x-4(2+3x)-(2(5x-3))=0
We add all the numbers together, and all the variables
x-4(3x+2)-(2(5x-3))=0
We multiply parentheses
x-12x-(2(5x-3))-8=0
We calculate terms in parentheses: -(2(5x-3)), so:We add all the numbers together, and all the variables
2(5x-3)
We multiply parentheses
10x-6
Back to the equation:
-(10x-6)
-11x-(10x-6)-8=0
We get rid of parentheses
-11x-10x+6-8=0
We add all the numbers together, and all the variables
-21x-2=0
We move all terms containing x to the left, all other terms to the right
-21x=2
x=2/-21
x=-2/21
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