x-3+-2(6+-2x)=2(2x+-5)

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Solution for x-3+-2(6+-2x)=2(2x+-5) equation: 



x-3+-2(6+-2x)=2(2x+-5)

We move all terms to the left:

x-3+-2(6+-2x)-(2(2x+-5))=0

We add all the numbers together, and all the variables

x-2(-2x)-(2(2x-5))-3+=0

We add all the numbers together, and all the variables

x-2(-2x)-(2(2x-5))=0

We multiply parentheses

x+4x-(2(2x-5))=0



We calculate terms in parentheses: -(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

5x-(4x-10)=0

We get rid of parentheses

5x-4x+10=0

We add all the numbers together, and all the variables

x+10=0

We move all terms containing x to the left, all other terms to the right

x=-10

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