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x-2=5(2x+5)
We move all terms to the left:
x-2-(5(2x+5))=0
We calculate terms in parentheses: -(5(2x+5)), so:We get rid of parentheses
5(2x+5)
We multiply parentheses
10x+25
Back to the equation:
-(10x+25)
x-10x-25-2=0
We add all the numbers together, and all the variables
-9x-27=0
We move all terms containing x to the left, all other terms to the right
-9x=27
x=27/-9
x=-3
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