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x-26=1/2x+13=3x-77
We move all terms to the left:
x-26-(1/2x+13)=0
Domain of the equation: 2x+13)!=0We get rid of parentheses
x∈R
x-1/2x-13-26=0
We multiply all the terms by the denominator
x*2x-13*2x-26*2x-1=0
Wy multiply elements
2x^2-26x-52x-1=0
We add all the numbers together, and all the variables
2x^2-78x-1=0
a = 2; b = -78; c = -1;
Δ = b2-4ac
Δ = -782-4·2·(-1)
Δ = 6092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6092}=\sqrt{4*1523}=\sqrt{4}*\sqrt{1523}=2\sqrt{1523}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-2\sqrt{1523}}{2*2}=\frac{78-2\sqrt{1523}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+2\sqrt{1523}}{2*2}=\frac{78+2\sqrt{1523}}{4} $
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