If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
X+1 = 0
X+1 = 0
X+1 = 0
X+1 = 0
x naleu017Cy do R
x belongs to the empty set
x-(X*(2/(X+1)))-2 = 0
x belongs to the empty set
| 4b+8=10 | | 8=9d+8 | | 5g^2+38g+21= | | h(5)=16t^2+112t+128 | | 5a=-65 | | 16t^2+112t+128=5 | | 10.5-x=6.1 | | 37=t+37 | | l=b-c/2 | | 4(m-2)=12 | | s/p=15 | | 9x+6=8x+13 | | p-9=s | | 3/5x-5+x-4=-1 | | 3rs^2(27r^3-8s^3)=0 | | -3b/8=-36 | | -8w-2=-6(w+3) | | -3(u-9)=-5u+25 | | 5v+15=-3(v+3) | | 3.5y=y+21.23+0.2 | | -4v+2(v+3)=22 | | 25x+10x+3=0 | | -18=-5x+3(x-2) | | (2x+3)(3x^2-22x+24)=0 | | 8y+7(y+8)=-4 | | y=3x^2-5x-8 | | 15b^2=36+33b | | 8+v/8=-12.48 | | 1.5=-6y+39.9 | | -13.7=-1.2+u/5 | | 4v+8=24 | | 292=-w+227 |