x-2+2x-3=3(x-2)

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Solution for x-2+2x-3=3(x-2) equation: 



x-2+2x-3=3(x-2)

We move all terms to the left:

x-2+2x-3-(3(x-2))=0

We add all the numbers together, and all the variables

3x-(3(x-2))-5=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

3x-3x+6-5=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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