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x-2*1/2x+4=-8
We move all terms to the left:
x-2*1/2x+4-(-8)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x-2*1/2x+12=0
We multiply all the terms by the denominator
x*2x+12*2x-2*1=0
We add all the numbers together, and all the variables
x*2x+12*2x-2=0
Wy multiply elements
2x^2+24x-2=0
a = 2; b = 24; c = -2;
Δ = b2-4ac
Δ = 242-4·2·(-2)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{37}}{2*2}=\frac{-24-4\sqrt{37}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{37}}{2*2}=\frac{-24+4\sqrt{37}}{4} $
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